Hand a struct member to a function

howdy all,

i'm new c++, hope isn't stupid question.  apologies in advance if that's case!

i have struct looks :

code: [select]


struct config_t
{
  unsigned int probe1value;
  unsigned int probe2value; 
}configuration;


i use struct in function :

code: [select]


void myfunction(int probe, int value)
{
 
  if(probe==1)
  {
    configuration.probe1value = value;
  }
  else if(probe==2)
  {
    configuration.probe2value = value;
  }
}



is possible hand struct member in don't have use ugly if loop in function?  stripped down version - there many more values in full deal, it's uglier.

i'm hoping end function looking :

code: [select]


void myfunction(<whateverthetypeis?> structmember, int value)
{
   structmember   = value;
}



any thoughts or different approaches more welcomed.

cheers,

doug.

you can pass pointer (struct config_t *p) structure or pass reference (struct config_t &p), not make copy of data , allows function modify original data.

you can pass data structure (struct config_t), in case copy of data created locally function.

i define type structure (typedef), make usage bit less clunky , more obvious.

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